help 2e^x - 5 =1
Have you learned about natural logs yet?
not so much
the rules for natural logs are the same as logs. Natural logs are just always a log to base e: \[\huge \log_e(x)\]
so with your problem, the first thing i would do is add 5 to both sides. The reason for this is because there are no log rules such that: \[\huge \ln(2*e^x-5)\] can be simplified.
These are really important to know and to know how to manipulate them. http://www.purplemath.com/modules/logrules.htm http://www.rapidtables.com/math/algebra/Ln.htm
ok
in the second link, the first three rules have some examples too, which is really awesome. we also see that \[\huge \ln(e^x)=x\] which will be really really handy here. Do you see why?
so i left with 2e^x=6 right
so far so good. Now knowing what i said about ln = natural log, what could you do to help you solve for x?
i could take away the 2
You can't take it away but you can....Divide by it on both sides. :D
ok so im left with e^x=3
So far so good. Now just use the rules for natural logs and you'll be done.
??
are u there
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