.. i need help finding the geometric mean of [4\sqrt{3}\] and [10\sqrt{3}\]

Question

hero · Answer

Hint: To find the geometric mean of two numbers, a and b, set up the following proportion:

$\large\frac{a}{x} = \frac{x}{b}$

hero · Answer

Then cross multiply. In this case

a = $4\sqrt{3}$
b = $10\sqrt{3}$

anonymous · Answer

but i still dont understand it.

hero · Answer

You don't know how to substitute numerical values for variables into the given formula?

anonymous · Answer

yes i have that part

hero · Answer

Okay, so you don't know how to cross multiply?

anonymous · Answer

i got the answer . thank you

hero · Answer

You got the answer? How?

hero · Answer

Did you do it yourself or did you use some other program? I suspect you used some other program. You're too confident in your answer, which you didn't even consider asking me whether or not it was correct.

anonymous · Answer

i did it my self i got 10.95 rounded up to 11.0

anonymous · Answer

it came to x^2=120 the square root of 120 is 10.954

hero · Answer

They gave you the problem in radicals, so your result should also be in radicals.

anonymous · Answer

2sqrt 30