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Mathematics 19 Online
OpenStudy (anonymous):

I need help with the problem attached.

OpenStudy (anonymous):

OpenStudy (anonymous):

take the integral from 0 to 90

OpenStudy (anonymous):

ya take the integral!

OpenStudy (anonymous):

I don't know how to do that.

OpenStudy (anonymous):

hahaa

OpenStudy (goten77):

\[\int\limits_{0}^{\pi/2}x+ \cos(x)\]

OpenStudy (anonymous):

ya this is the way!

OpenStudy (goten77):

then you have \[x ^{2}/2 + \sin(x) + c\]

OpenStudy (anonymous):

now put the limits!

OpenStudy (anonymous):

you dont need c

OpenStudy (goten77):

well ye u dont but i put it anyways just so it looks smart

OpenStudy (anonymous):

got the answer?

OpenStudy (anonymous):

I still don't realize what the next step will be after.

OpenStudy (anonymous):

what? just put in the values!

OpenStudy (anonymous):

I suck at trigs!

OpenStudy (anonymous):

its easy want to learn it this is just the basics!

OpenStudy (goten77):

i feel like i did something wrong...

OpenStudy (anonymous):

I have no idea..

OpenStudy (anonymous):

no its wrong

OpenStudy (goten77):

oh i found my error now

OpenStudy (anonymous):

divide it by 4

OpenStudy (anonymous):

not 2

OpenStudy (goten77):

\[((\pi/2)^{2}/2) + 1\]

OpenStudy (anonymous):

ya thats right!

OpenStudy (anonymous):

So that's what I put down for the answer?

OpenStudy (goten77):

it reduces to \[(\pi ^{2}/4) + 1\]

OpenStudy (anonymous):

Okay, thanks. I need help with just one more problem.

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