Find the perimeter of xyz x(-6,2) y(2,8) x(-6,8)

I forgot the distance thingy formula

Question

Find the perimeter of xyz x(-6,2) y(2,8) x(-6,8)

I forgot the distance thingy formula

lgbasallote · Answer

$$\text{distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$

lgbasallote · Answer

unless it's 3d...

lgbasallote · Answer

it becomes $$\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}$$

anonymous · Answer

it's not  3-d haha okay so now can you help me with the question? ahah
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lgbasallote · Answer

lol good for you :)

and i really cant help because i cannot imagine what your question is

anonymous · Answer

oh trianglexyz

anonymous · Answer

does that help

anonymous · Answer

hello guys?

lgbasallote · Answer

seriously...draw it...

anonymous · Answer

they don't show a drawing. they literilly just say find the perimeter of xyz.

anonymous · Answer

If I will give you the formula then can you do it ??

anonymous · Answer

You know the formula very much all just you have to do is to use that 3 times.

Can you do that @Steeben

anonymous · Answer

so it's rad(2+6)^2+(8-2)^2

anonymous · Answer

64+36 = 100 then 10?

anonymous · Answer

Go ahead  use this for other 2 points left..

anonymous · Answer

rad(-6-2)^2+(8-8)^2

anonymous · Answer

64... 8

anonymous · Answer

This one is one distance you have found..

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