Question

Henry grabs one shoe at a time at random without replacement from a box of shoes in his closet. The box contains 2 brown shoes, 4 black shoes, and 4 sneakers. What is the probability that the first two shoes he chooses will be brown? Round to the nearest percent if necessary.

Answer 1

2/10*1/9

Answer 2

good catch

Answer 3

\[P(2brown)=\frac {\left(\begin{matrix}2 \\ 2\end{matrix}\right)\left(\begin{matrix}8 \\ 0\end{matrix}\right)}{\left(\begin{matrix}10 \\ 2\end{matrix}\right)}\]
\[P(2brown)=\frac{2}{10\times 9}\]

Answer 4

@amberose10 Have you calculated the answer yet?

Answer 5

the easiet way to do the question is

P(brown shoe) = 2/10 1st selection

then there are only 9 shoes left and 1 brown show

P(brown shoe) = 1/9 2nd selection

so P( Brown, Brown) = 2/10 x 1/9

Answer 6

i dont get it

Answer 7

i need help with this question

Answer 8

ill give a medal