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What is the sum of a 6-term geometric series if the first term is 19 and the last term is 319,333?
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etermine the three cubic roots of 8.give the answer in the form of a+bj.also give the main root in the exponential form
dude that sounds so complex...
Ya cos cubic roots of 8 is 2.2.2 so wanna know how to solve it
the 6th term is 319333 you need to find r so \[319333 = 19\times r^{6 -1}\] \[\frac{319333}{19} = r^5\] then\[ r = \sqrt[5]{\frac{319333}{19}}\] Once you know r then use \[S_{6} = \frac{19(r^6 -1)}{r -1}\] that will give you the sum of the 6 terms
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