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Mathematics 14 Online
OpenStudy (anonymous):

What are the directrices of the hyperbola given by the equation x^2/25 - y^2/81= 1?

OpenStudy (anonymous):

\[y=\pm(b/a)x\]

OpenStudy (anonymous):

Ok Thank you :)

OpenStudy (anonymous):

not sure actually......please confiem

OpenStudy (anonymous):

It's wrong.

OpenStudy (anonymous):

the answer choices are: x= \[x = \pm25\sqrt{106}/106\]

OpenStudy (anonymous):

thats one of the answer choices

OpenStudy (anonymous):

sorry i was writing asymptotes equation..

OpenStudy (anonymous):

Do you happen to know the formula for directrix? :S

OpenStudy (anonymous):

its \[x=\pm (a/e)\]

OpenStudy (anonymous):

e is eccentricity of hyperbola given by \[e=\sqrt{1+(b ^{2}/a ^{2})}\]

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

Thank you

OpenStudy (anonymous):

welcome////////

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