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What are the directrices of the hyperbola given by the equation x^2/25 - y^2/81= 1?
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\[y=\pm(b/a)x\]
Ok Thank you :)
not sure actually......please confiem
It's wrong.
the answer choices are: x= \[x = \pm25\sqrt{106}/106\]
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thats one of the answer choices
sorry i was writing asymptotes equation..
Do you happen to know the formula for directrix? :S
its \[x=\pm (a/e)\]
e is eccentricity of hyperbola given by \[e=\sqrt{1+(b ^{2}/a ^{2})}\]
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oh ok
Thank you
welcome////////
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