how dp you simplify this problem? 3+1/4 / (5/6+2^2)
is it \[\frac{3 +\frac{1}{4}}{\frac{5}{6}+2^2} \]?
yes
then do it step by step. first what is 2^2?
4
now what is 5/6 + 4 you first put the 4 over a common denominator of 6 like this \[ \frac{4}{1}\cdot \frac{6}{6}= \frac{24}{6}\] now add 5/6 + 24/6
If you need more help with fractions, maybe this will help http://www.khanacademy.org/math/arithmetic/fractions/v/adding-and-subtracting-fractions
sorry was writing it down at the same time
29/6 is what i get
OK, that is the bottom (denominator). Let's look at the top now. what is 3+1/4 ? (put 3 over a common denominator of 4 and then add)
12/4
add that with 1/4 and i get 13/4
yes. now we use the great trick when dealing with fractions: if you multiply the top and bottom by the same thing, you do not change its value (that is how we changed 3 into 12/4 .... the whole number 3 can be thought of as having a 1 in the "bottom") so we have \[ \frac{\frac{13}{4}}{\frac{29}{6} }\] multiply top and bottom by 6/29
do you find common or just mulitply
where do you get that you multiply both by 6/29
just multiply. like this \[ \frac{\frac{13}{4} \cdot \frac{6}{29}}{ \frac{29}{6} \cdot \frac{6}{29}}\]
79/116 / 1 is what i get cause the bottom cancells out eash other right
the reason we pick 6/29 is it makes the bottom equal 1, so we can ignore it anything divided by 1 is itself. so the problem becomes \[ \frac{13}{4} \cdot \frac{6}{29} \] Before multiplying it out I would divide the 4 by 2 and the 6 by 2 to simplify it \[ \frac{13}{2} \cdot \frac{3}{29} \]
check your multiplication
39/58
yes, and I think that is in lowest (simplest) form.
ok i was lost because when you go to freemathhelp.com they get 177/58
If you multiplied out 13*6/ (4*29) you get 78/116 you can then simplify that to 39/58
It depends exactly what the original problem is. Can you type in the problem with the correct parens, or show the original?
give me a min i will try to copy and past the problem as it is wrote. i have to sign back in to get it out of the book.
it wont let me but it is 3+1/4 for the num and 5/6+2^2 in the den
I think that the way we did it is right because that is what i orig had for the answer
I can get 177/58 if the original problem is \[ 3 + \frac{\frac{1}{4}}{\frac{5}{6}+2^2} \]
how did you
get that so i can put both down just in case
If you use order of operations, that is how you would interpret what you posted: 3+1/4 / (5/6+2^2) however, so many people mean (3+1/4) / (5/6+2^2) that I assumed that was the problem.
how did you get the other answer
the bottom is the same as before= 29/6 so multiply top and bottom by 6/29 \[\frac{1}{4}\cdot \frac{6}{29} \]
simplify by dividing the 6 and the 4 by 2, and you get 3/58
now the problem is 3 + 3/58 put 3 over a common denominator of 58
you get \[ \frac{174}{58}+\frac{3}{58} = \frac{177}{58} \]
sorry got bumped i am going to look at what you put before i got bumped
ty i finally got it do you have time to help with more
x^2-2x+5x-(-x^2+7x)
distribute the -1*(-x^2+7x) as the first step. that means multiply every term inside the parens by -1
I get the neg and posit mixed up
x^2+-7x i think
-(-x^2+7x) is the same as -1*(-x^2+7x) which becomes -1* -x^2 + -1*7x - times - is + (2 minuses become a plus, a minus and a plus become a minus) so we get x^2 -7x
or x^2 + -7x though people generally write it as x^2 -7x (fewer symbols) so now the problem is x^2-2x+5x+x^2 -7x combine "like terms" x^2 goes with x^2 , x with x,
It sounds like it's tough out there, getting bumped and frozen!
yes sorry
looking over what you did
so do you get get 2x^2+14x
how did you get 14 x ? x^2-2x+5x+x^2 -7x we can "commute" the terms (change their order) x^2+x^2 + 5x -2x -7x if we think x^2 are cows and x are horses, how many cows and horses? or use this idea (x^2+x^2) + (5x -2x -7x) factor out x^2 from the first set of parens and x out of the second set (1+1)*x^2 + (5-2-7)*x
not sure let me look
the pos and neg confuse me is whyi get 2x^2+-4 i know that is not right i am still confused
the 5-2-7 is what confuses me
you mean 2x^2 + -4x (there is an x there, right?) or more simply 2x^2 -4x about the signs you can write , for example 8 + -4 or 8-4 they mean the same thing.
5-2-7 means 5 minus 2 = 3 and then 3 minus 7 which is -4 or think of it as 5 + (-2) + (-7) you are adding 3 numbers
here is a 5 minute video http://www.khanacademy.org/math/arithmetic/negative-numbers/v/adding-negative-numbers that might clear it up?
ok that makes it easier so now we have 2x^2-4x
yes. what to do next (if anything) depends on the question. often people would factor it to get 2x(x-2) but it depends...
ok how did you get that
another 5 min video http://www.khanacademy.org/math/arithmetic/number-properties/v/the-distributive-property
it says to simplify
i think what you got is what they want
to factor 2x^2-4x notice that both terms can be divided by 2. so we divide both terms by 2, but put parens around the answer and put the 2 "out front" 2(x^2-2x) (we can "undo" this by multiplying each term by 2 to get 2x^2 -4 ) notice that both terms can be divided by x. Do the same thing 2x(x-2)
do you have time for 1 more
solve -9y-12(2-3y)=-25-2(y+6)
*(we can "undo" this by multiplying each term by 2 to get 2x^2 -4x ) fixed a typo
if you distribute the -12 on the left hand side, what do you get?
-24+36y
ok, now simplify the left side -9y-24+36y
-24+27y
ok, so we have, so far -24+27y = -25-2(y+6) distribute the -2 on the right. And write out the whole equation
-25-2y-12 -24+27y=-25-2y-12
I would combine the numbers on the right side: -25-12 = -37 add +24 to both sides of the equation. what do we get. Again write the whole equation.
27y=-13-2y
what do you think we should do next?
add 2y to both sides
we get?
y=-13/29 i hope
yes. looks good.
ty soooo much i have more but dont want to stress you out lol
post your questions, people will help you. but I am late as it is...
ty again
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