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log 81 3 = 1/4
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the 81 is supposed to be below the log
correct: 81^1/4 = 3
\[\log_{81}(3) = \frac{1}{4}\] \[\huge \log_a(x) = b \implies a^b = x\]
Here a = 81 b = 1/4 and x = 3 Try to solve for x ..
but you already said wat x was its 3
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\[\huge (81)^{\frac{1}{4}} \implies (3^4)^{\frac{1}{4}} \implies (3)^{4 \times \frac{1}{4}} \implies \color{green}{3}\]
Oh sorry don't solve for x
lol
Are you asking that they are correct or not ??
Ha ha ha.. I misread it...
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i understand it now its just switching them around basically
Yes well done ..
:)
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