Match the equation with the correct solution. log 4 x + log 4 9 = log 4 27
here are the answer choices 3 2 -2 5 12 4
use the log property\[\large \log_a x+\log_a y=\log_a(xy)\]to combine the terms on the left, then raise 4 to the power of both sides to get rid of the logarithm\[\huge a^{\log_ax}=x\]
how do i do that?
well for instance\[\log5+\log2=\log(5\times2)=\log(10)\]do that trick with the terms on the left hand side of your equation
can i plug that into my calc?
use log laws for addition \[loa_{a} b + \log_{a} c = \log_{a} bc\] so you have on the left hand side \[\log_{4} x + \log_{4} 9 = \log_{4} 9x \] so solve 9x = 27
using logs with bases other than 10 or e is not common to many calculators best to go about it by hand
huh?
@campbell_st used exactly what I said above, and in my opinion gave a bit too much info you should certainly be able to take it from where he left off.
yes i got 3 but how did he get to that point?
how did he get 9x=27?
because the logs are in the same form... \[\log_{4} 9x = \log_{4} 27\] you can just equate the 9x and 27
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