Frank kicks a soccer ball off the ground and in the air with an initial velocity of 30 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches?
14.1 feet
13.7 feet
13.2 feet
15.2 feet
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OpenStudy (anonymous):
ok
will use calculus based approach
OpenStudy (anonymous):
take derivative
h'(t)=-32t+v
OpenStudy (anonymous):
set it equal to zero to get the critical point
OpenStudy (anonymous):
-32t+v=0
but v=30 ft given
32t=v
32t=30
t=30/32
OpenStudy (anonymous):
are you getting this @MeganLewis ??
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OpenStudy (anonymous):
yes. but t=30/32 doesnt equal any of my choices.
OpenStudy (anonymous):
well for that wait a little :P
OpenStudy (anonymous):
t=30/32=0.9375
OpenStudy (anonymous):
put that value of t=0.9375 in the original equation H(t) = −16t2 + vt + s
and let me know what you got
OpenStudy (anonymous):
and yes use v=30 and s=0 in the above
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OpenStudy (anonymous):
H(0.9375)=-16(0.9375)^2+30(0.9375)+0
OpenStudy (anonymous):
H=14.0625 feet
OpenStudy (anonymous):
is it ok??
OpenStudy (anonymous):
14.1 is the close one
OpenStudy (anonymous):
Okay thank you!
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