Mathematics
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OpenStudy (alexwee123):
hard problem :(
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OpenStudy (anonymous):
What's the problem?
OpenStudy (alexwee123):
evaulate (x^3e^x^2) / (x^2 + 1)^2 dx
OpenStudy (lgbasallote):
integral right?
OpenStudy (alexwee123):
yep :(
OpenStudy (anonymous):
\[(x ^{3}e ^{x ^{2}})/(x ^{2}+1)^{2}dx\] Look like this?
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OpenStudy (lgbasallote):
\[\Large \int \frac{x^3 e^{x^2}}{(x^2 + 1)^2} dx\]
rught?
OpenStudy (alexwee123):
ya @lgbasallote
OpenStudy (alexwee123):
do i do u-sub?
OpenStudy (anonymous):
my first guess would have been u=x^2
OpenStudy (lgbasallote):
my first guess was partial fractions
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OpenStudy (alexwee123):
wat about integration by parts?
OpenStudy (anonymous):
will follow too I guess, but I thought I could make it a bit easier with a substitution at first, so far, I didn't manage though *grins*.
OpenStudy (lgbasallote):
actually....you *do* sub by x^2 first
OpenStudy (anonymous):
yeh, I think I got it now
\[ u= x^2 \longrightarrow du=2xdx \]
In the numerator you have have this annoying x^3
\[x^2 \cdot x dx = u \frac{1}{2}du \]
OpenStudy (lgbasallote):
yup
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OpenStudy (anonymous):
looks a bit messy but then, if I didn't make any careless mistakes as I usually do
\[ \frac{1}{2} \int \frac{ue^u }{(u+1)^2}\]
OpenStudy (lgbasallote):
so now integral by parts
OpenStudy (anonymous):
did you get the same @lgbasallote ?
OpenStudy (anonymous):
ok, good.
OpenStudy (anonymous):
\[\large \large \frac{\frac{1}{2}e^{x^2}}{1+x^2}+C\]
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OpenStudy (alexwee123):
thx :D