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Mathematics 25 Online
OpenStudy (alexwee123):

hard problem :(

OpenStudy (anonymous):

What's the problem?

OpenStudy (alexwee123):

evaulate (x^3e^x^2) / (x^2 + 1)^2 dx

OpenStudy (lgbasallote):

integral right?

OpenStudy (alexwee123):

yep :(

OpenStudy (anonymous):

\[(x ^{3}e ^{x ^{2}})/(x ^{2}+1)^{2}dx\] Look like this?

OpenStudy (lgbasallote):

\[\Large \int \frac{x^3 e^{x^2}}{(x^2 + 1)^2} dx\] rught?

OpenStudy (alexwee123):

ya @lgbasallote

OpenStudy (alexwee123):

do i do u-sub?

OpenStudy (anonymous):

my first guess would have been u=x^2

OpenStudy (lgbasallote):

my first guess was partial fractions

OpenStudy (alexwee123):

wat about integration by parts?

OpenStudy (anonymous):

will follow too I guess, but I thought I could make it a bit easier with a substitution at first, so far, I didn't manage though *grins*.

OpenStudy (lgbasallote):

actually....you *do* sub by x^2 first

OpenStudy (anonymous):

yeh, I think I got it now \[ u= x^2 \longrightarrow du=2xdx \] In the numerator you have have this annoying x^3 \[x^2 \cdot x dx = u \frac{1}{2}du \]

OpenStudy (lgbasallote):

yup

OpenStudy (anonymous):

looks a bit messy but then, if I didn't make any careless mistakes as I usually do \[ \frac{1}{2} \int \frac{ue^u }{(u+1)^2}\]

OpenStudy (lgbasallote):

so now integral by parts

OpenStudy (anonymous):

did you get the same @lgbasallote ?

OpenStudy (anonymous):

ok, good.

OpenStudy (anonymous):

\[\large \large \frac{\frac{1}{2}e^{x^2}}{1+x^2}+C\]

OpenStudy (alexwee123):

thx :D

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