Question

I need help with an attached problem please.

Answer 1

2x^3-5=u
6x^2dx = du-----> integral(sqrt(u)*du/2
=u^(3/2)/2 + constant

Answer 2

\[\int\limits_{}^{}1/\sqrt{u}\]

Answer 3

Shouldn't it be u^(3/2)/3+C?

Answer 4

yes yes my mistake :/

Answer 5

You can \[let\ u = 2x^3-5;\ du=6x^2\]
\[\int3x^2\sqrt{2x^3-5} = \frac{1}{2}\int\sqrt{u}\ du\]

Answer 6

(u^3/2)*2/3*1/2 so (u^3/2)*1/3

Answer 7

\[=\frac{1}{3}u^{\frac{3}{2}}+C\]

Answer 8

Ugh I got: