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I need help with an attached problem please.
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2x^3-5=u 6x^2dx = du-----> integral(sqrt(u)*du/2 =u^(3/2)/2 + constant
\[\int\limits_{}^{}1/\sqrt{u}\]
Shouldn't it be u^(3/2)/3+C?
yes yes my mistake :/
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You can \[let\ u = 2x^3-5;\ du=6x^2\] \[\int3x^2\sqrt{2x^3-5} = \frac{1}{2}\int\sqrt{u}\ du\]
(u^3/2)*2/3*1/2 so (u^3/2)*1/3
\[=\frac{1}{3}u^{\frac{3}{2}}+C\]
Ugh I got:
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