Question

write (6x^2-13x-5)/(9x^3-x) in lowest terms

Answer 1

\[\Large \frac{6x^2 - 14x - 5}{9x^3 - x} \implies \frac{(3x+1)(2x-5)}{x(9x^2 - 1)} \implies \frac{(3x+1)(2x-5)}{x(3x +1)(3x-1)}\]
does that help?

Answer 2

not reLLY cant see the whole thing

Answer 3

its 6x^2-13x-5

Answer 4

uhmm yeah..that was just a typo hehe

Answer 5

the next steps followed the 13x...i jsut wrote 13x wrongly

Answer 6

so do you get it? i just factored out the numerator and denominator

Answer 7

well the last part i cant see for some reason hehe

Answer 8

what happen after is factored?

Answer 9

the last part is \[\Large \frac{(3x+1)(2x-5)}{x(3x+1)(3x-1)}\]

Answer 10

do you see what you're going to do now?

Answer 11

elimnate right

Answer 12

yup

Answer 13

then you have the answer

Answer 14

gracias

Answer 15

de nada