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Mathematics 21 Online
OpenStudy (anonymous):

(2x^-2+y^-2) divide by (x^-1-y^-1) simplify complex fraction.

OpenStudy (anonymous):

Okay..

OpenStudy (anonymous):

???

OpenStudy (anonymous):

one second. these get messy.

OpenStudy (anonymous):

Okay so basically this is what you do, step by step?

OpenStudy (anonymous):

i figured

OpenStudy (anonymous):

watch.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so according to your exponent laws, any variable divided by another variable is a subtraction of exponents. so x^2 divided by 2 is x^2-1, so x.

OpenStudy (anonymous):

Negative exponents make them become the denominator. the fraction is flipped.

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

So what you have to do is separate it to 2x^-2 divided by x^-1 -y^-1 +y^-2 divided by x^-1 -y^-1

OpenStudy (anonymous):

then you flip.

OpenStudy (anonymous):

once all the fractions are flipped, you get positive exponents.

OpenStudy (anonymous):

can u show me how would it actually look

OpenStudy (anonymous):

you can then simplify, remember your exponent laws!

OpenStudy (anonymous):

right

OpenStudy (anonymous):

so this is what you get once you flip them:

OpenStudy (anonymous):

By the way, forget that separation of fractions thing, you won’t need that yet

OpenStudy (anonymous):

just take your old equation, the first one

OpenStudy (anonymous):

flip it. You will get:

OpenStudy (anonymous):

x\[x^1 - y^1 /2x^2\]

OpenStudy (anonymous):

i thin thats wrong

OpenStudy (anonymous):

answer is 2y^2+x^2/ xy(y-x)

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