Question

A ball was thrown at 50miles per second and it was to reach 3000miles what is the angle that it needs to be thrown to hit the destination? with the formula r=(1/32)(Vo)^2sin2

Answer 1

where r is...what?

Answer 2

What?

Answer 3

you gave the formula r=(1/32)(Vo)^2sin2

what does r represent?

Answer 4

The angle I think

Answer 5

No, it's 3000 miles...I'm pretty sure

Answer 6

so where does the angle come in?

Answer 7

This is what I got Vo=50m/s 50*5280=26400ft/s
r=3000 miles=15840000 ft
r=(1/32)(Vo)^2sin2t
15840000*32= (26400)2 sin2t
0.7273=sin2t
2t=46.6584
t= 23.3292 degrees

Answer 8

is it \[\large r = \frac{1}{32} (V_o)^2\sin 2\]
or
\[\Large r = \frac{1}{32} (v_o)^2 \sin \theta\]

Answer 9

THe second one

Answer 10

why did you multiply 5280 to 50 again?

Answer 11

so u gotta work in ft????

Answer 12

everything is in miles neways

Answer 13

That's what I'm thinking...

Answer 14

ok well either way u shld get the same answer lets try it out in miles

Answer 15

Alright...

Answer 16

nooo u r right for some reason u gotta work in ft

Answer 17

not this again...

Answer 18

hahahha

Answer 19

Am I right?

Answer 20

Like if u are working in ft that is correct. U got that answer from yahoo answers :P

Answer 21

Ya i just did it like a bunch of times and like I am figuring u have to work in ft so ya there is ur answer

Answer 22

What's yahoo answers?