f point C is the midpoint of /AB , what is the coordinate of point B? (–9, 2) (–3, 1) (0, –7) (–1, –8)
mid-point again LOL
read pages 2 and on - http://finedrafts.com/files/Larson%20PreCal%208th/Larson%20Precal%20CH1.pdf
mid-point formula is in page 5
so is A
plz is it
did you also read about the distance?
yes
bout c
\[\large Midpoint(x,y) = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})\] Here: \((x,y) = (-3, -5)\) , \((x_1, y_1) = (-6, -3)\) and we have to find \(x_2\) and \(y_2\) \[\large Midpoint(-3,-5) = (\frac{-6 + x_2}{2}, \frac{-3 + y_2}{2})\] Try to equate x coordinate of Left side with the right side.. Similary do for y coordinates on both the sides.. and find \(x_2\) and \(y_2\)...
ok so is should be A or c
for x, what do you need to add to -6 so when you divide it by 2, you get -3? the same technique for y.
Simply solve this: \[\frac{-6 + x_2}{2} = -3\] Multiply 2 both the sides and then add 6 both the sides and tell me what are you getting for \(x_2\)..
D, [-6+(-9)]/2 = -3?
What is this @panlac01
asking her why she's choosing A as an answer.
indirectly, of course
when you get a chance, Diana, please review http://www.purplemath.com/modules/negative.htm
ok Thinks
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