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Mathematics 18 Online
OpenStudy (anonymous):

f point C is the midpoint of /AB , what is the coordinate of point B? (–9, 2) (–3, 1) (0, –7) (–1, –8)

OpenStudy (anonymous):

OpenStudy (anonymous):

mid-point again LOL

OpenStudy (anonymous):

read pages 2 and on - http://finedrafts.com/files/Larson%20PreCal%208th/Larson%20Precal%20CH1.pdf

OpenStudy (anonymous):

mid-point formula is in page 5

OpenStudy (anonymous):

so is A

OpenStudy (anonymous):

plz is it

OpenStudy (anonymous):

did you also read about the distance?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

bout c

OpenStudy (anonymous):

\[\large Midpoint(x,y) = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})\] Here: \((x,y) = (-3, -5)\) , \((x_1, y_1) = (-6, -3)\) and we have to find \(x_2\) and \(y_2\) \[\large Midpoint(-3,-5) = (\frac{-6 + x_2}{2}, \frac{-3 + y_2}{2})\] Try to equate x coordinate of Left side with the right side.. Similary do for y coordinates on both the sides.. and find \(x_2\) and \(y_2\)...

OpenStudy (anonymous):

ok so is should be A or c

OpenStudy (anonymous):

for x, what do you need to add to -6 so when you divide it by 2, you get -3? the same technique for y.

OpenStudy (anonymous):

Simply solve this: \[\frac{-6 + x_2}{2} = -3\] Multiply 2 both the sides and then add 6 both the sides and tell me what are you getting for \(x_2\)..

OpenStudy (anonymous):

D, [-6+(-9)]/2 = -3?

OpenStudy (anonymous):

What is this @panlac01

OpenStudy (anonymous):

asking her why she's choosing A as an answer.

OpenStudy (anonymous):

indirectly, of course

OpenStudy (anonymous):

when you get a chance, Diana, please review http://www.purplemath.com/modules/negative.htm

OpenStudy (anonymous):

ok Thinks

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