Question

differentiate x^(-1) twice....please

Answer 1

\[d ^{2}/dx ^{2}(1/x) \implies d/dx(-1/x ^{2})\implies 2/x ^{3}\]

Answer 2

\[d/dx(x ^{n})=nx ^{n-1}\]

Answer 3

n is any integer

Answer 4

ok, and just regular x would first become x^(-1), then -x^(-2)?

Answer 5

\[\frac{d}{dx} x^{-1} \implies -1(x)^{-1 - 1} \implies -x^{-2}\]
\[\frac{d}{dx} x^{-2} \implies -2 (x)^{-2 - 1} \implies -2x^{-3}\]

Answer 6

sorry that should be positive

Answer 7

thank you