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lim n-> infinity 1/n[(1/n)^7+(2/n)^7+(3/n)^7+(4/n)^7+...+(n/n)^7]
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it will always be zero. I think, so get confirmation. but the larger the number is on the denominator the smaller the actual number becomes. IE: 1/2 is way larger than 1/100000000000...
so actually doing the math would be, and don't tell a teacher, a waste of time
sure
oh!
i just dont get it why this problem is so hard to solve
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is said that we need to evaluate the problem
so as n approaches infinity, the equation would end up looking like (1/inf.). = 0
k thank
got it? you will use this a lot an other maths too, so remember it
its a fun short cut
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k
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