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Mathematics 15 Online
OpenStudy (anonymous):

find the radius of convergence and interval of convergence of the power series ∞∑ n=1 x^n/(n^2*3^n)

OpenStudy (turingtest):

have you tried the ratio test?

OpenStudy (anonymous):

I dont even know where to start. i dont understand series and sequences.

OpenStudy (anonymous):

lim n->infinity of An+1/An

OpenStudy (turingtest):

that is a problem if you are doing power series and inervals of convergence and don't understand the basics... but @nuk64 is pointing you the right way

OpenStudy (anonymous):

sorry, that's in absolute terms. so it's: lim as n-> infinity of |An+1/An|

OpenStudy (turingtest):

@dillpickles do you know what nuk64 means by \[\lim_{n\to\infty}|{a_{n+1}\over a_n}|\]?

OpenStudy (anonymous):

Kind of. I understand that you plug in n+1 to the n's in the equation but my calc book is just confusing me. It has the equation with the n+1's multiplied by the inverse of the equation i think.. i dont understand why you need to multiply by the inverse.

OpenStudy (turingtest):

well I think you are looking at it like\[\lim_{n\to\infty}|a_{n+1}\cdot\frac1{a_n}|\]which is the same as I wrote above (it is still a ratio, hence the name ration test; it tests the limits between successive terms as \(n\to\infty\)

OpenStudy (turingtest):

so what is \(a_{n+1}\) ?

OpenStudy (anonymous):

oh you are right haha hold on let me figure it out and i will show you

OpenStudy (anonymous):

try using this as an example. http://openstudy.com/users/nuk64#/updates/500e3969e4b0ed432e109689 i had trouble with this myself, but it's not too bad once you figure it out. :)

OpenStudy (anonymous):

oh and this one. http://openstudy.com/users/nuk64#/updates/500f4217e4b009397c67652c

OpenStudy (anonymous):

|dw:1343362139339:dw|

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