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if f(x)=3lnx+C and f(e)=2 then find the value of C help please<3
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\[f(x) = 3\ln x + C\] \[f(e) = 2\] just substitute the x in f(x) with e and equate it to 2 \[f(e) = 3\ln (e) + C \] \[3 \ln (e) + C = 2\] \[3(1) + C = 2\] \[3 + C = 2\] \[C = 2- 3\] \[C = -1\] got it?
oh ok but may i ask why you made lnx = 1?
or ln(e)
because ln is \(\large \log_e\) therefore \[\large \ln e = \log_e e = 1\]
ohh ok thankss
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welcome ^_^
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