Question

Rationalize the denominator of

Answer 1

\[4 \over 6-\sqrt{7}\]

Answer 2

@zepp :D

Answer 3

\[\LARGE \frac{c}{A-\sqrt{B}}\rightarrow\frac{c(A+\sqrt{B})}{(A-\sqrt{B})(A+\sqrt{B})}\]

Answer 4

And use the property \(\large (a-b)(a+b)=a^2-b^2\)

Answer 5

k :) ill giv it a try :)

Answer 6

\[24+4\sqrt{7}\over29\]

Answer 7

yes? :D

Answer 8

represent\[3x ^{5\over7}\]in radical form?

Answer 9

i dont exactly understand this ^ :)

Answer 10

\[\huge3 \sqrt[7]{x ^{5}}\]

Answer 11

i think its that :)

Answer 12

Then you are right..

Answer 13

so if i turn \[\huge \sqrt[6]{x ^{5}}\]into exponent form i would get\[\huge x ^{5\over6}\]?? :)

Answer 14

\[\huge (x)^{\frac{m}{n}} \implies \sqrt[n]{x ^{m}}\]

Answer 15

Yes correct..

Answer 16

\[\large \frac{4}{6-\sqrt{7}}=\frac{4(6+\sqrt{7})}{6^2-\sqrt{7}^2}=\frac{6*4+4\sqrt{7}}{36-7}=\frac{24+4\sqrt{7}}{29}\]

Answer 17

Correct :D

Answer 18

how would i do \[\huge x ^{2\over5}\times x^{2\over9}\]? :)

Answer 19

does it need common denominators? :)

Answer 20

It needs common base only.

Answer 21

\[\huge (x)^a \cdot (x)^b = (x)^{a+b}\]

Answer 22

so \[\huge x ^{18\over45}\times x^{10\over45}\]

Answer 23

Going well..

Answer 24

\[x^{28/45}\]

Answer 25

Yes you are right...
Well Done..

Answer 26

okay and when dividing powers you subtract right??

Answer 27

Yes very right..

Answer 28

\[\huge \frac{x^a}{x^b} = x^{a-b}\]

Answer 29

and when raising a power to another power we multiply?

Answer 30

Yes..

Answer 31

\[\huge (x^a)^b = (x)^{a \times b}\]

Answer 32

wats \[i^{-37}\]??

Answer 33

i^37

Answer 34

okay well gtg...thanks for the help :D

Answer 35

\[i^2 = -1\]

\[i^3 = -i\]

\[i^4 = 1\]

Do you want to find its value ??

Answer 36

yes i did :)

Answer 37

What you got as answer??

Answer 38

simplify \[\huge i ^{37}\]

Answer 39

i don get how to do it

Answer 40

See first divide 37 by 4 and find the remainder..

Answer 41

why 4?

Answer 42

i=sqrt(-1)
i^2=-1
i^3=-i
i^4=i
i^5=sqrt(-1)
i^6=-1
i^7=-i
i^8=i

Do you see the relationship and repetition? Simply divide 37 by 4, and use the remainder to determine what the power will be, and then use the above table thingo.

Answer 43

because i^4 = 1 it will be easy for you..

Answer 44

9.25?

Answer 45

The series repeats itself after the fourth power.

Answer 46

no no not this way..

37/4 remainder 1 I think..

Answer 47

im.....not getting it :\

Answer 48

i^36=1
i^37=i^1

That is why.