If the distance between two objects is increased to four times the original distance, how will that increase change the force of attraction between the objects?
*repost* \[ F = G \frac{m_1 m_2}{r^2}\] the new radius is two times the old radius so \(r_n=4r \) \[F=G\frac{m_1m_2}{16r^2} = \frac{1}{16}G \frac{m_1m_2}{r^2} = \frac{1}{16}F\] works exactly the same.
incorrect
what is the answer then?, I am pretty sure that the algebra is correct.
besides that I didn't change my statement up there, the new radius is four times the original distance.
i chose that before and it was wrong
where does radius come from?
this is physics/chemistry
Hmm I will invite and ask @TuringTest then, maybe he notices what I did wrong
@TuringTest is offline
well all I did is substitution, hence I believe it is correct and it makes sense too, you know the original formula for newtons universal law of gravitation right?
It is easy to see, if you increase the radius between two objects, the gravitation attraction matters less, so the earth attracts the moon, but earths gravity means nothing for titan.
okay im going to go with that, i hope its not wrong!!
are you 100% sure
you better read up on gravitation and how it works yourself, I am not sure what test you are attending or which program you use,
maybe my friend @mukushla might want to check my algebra as well
Its not algebra
yes I know what you mean, but the laws of physics are constrained by the laws of mathematics.
just because it's a physical formula, doesn't mean that you can't apply the laws of algebra/calculus/differential
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