Question

Two similar cylinders have heights 12 inches and 18 inches.

What is the ratio of their surface areas?

Answer 1

@Ganpat @SmoothMath @experimentX

Answer 2

@Calcmathlete

Answer 3

Surface are for cylinder..

Surface Area = Areas of top and bottom +Area of the side
Surface Area = 2(Area of top) + (perimeter of top)* height

since are is not given... i will assume the radius will be the same..

So A1/ A2 = (perimeter of top)1 * height 1 / (perimeter of top)2 * height22

A1 / A2 = 2*pi*r* h1 / 2* pi*r* h2..

A1 / A2 = 12 / 18 = 2 /3...

Answer 4

Ok. The ratio between two similar figures' sides and lengths is a : b. The ratio between areas is \(a^2 : b^2\).So if a : b is 12 : 18 which when simplifies is 2 : 3, what is \(a^2 : b^2\)?

Answer 5

THANKS GUYS

Answer 6

np :)