Two similar cylinders have heights 12 inches and 18 inches.

What is the ratio of their surface areas?

Question

Two similar cylinders have heights 12 inches and 18 inches. 

What is the ratio of their surface areas?

anonymous · Answer

@Ganpat @SmoothMath @experimentX

anonymous · Answer

@Calcmathlete

ganpat · Answer

Surface are for cylinder..

Surface Area = Areas of top and bottom +Area of the side
Surface Area = 2(Area of top) + (perimeter of top)* height

since are is not given... i will assume the radius will be the same.. 

So A1/ A2 = (perimeter of top)1 * height 1 / (perimeter of top)2 * height22

A1 / A2 = 2*pi*r* h1 / 2* pi*r* h2..

A1 / A2 = 12 / 18 = 2 /3...

anonymous · Answer

Ok. The ratio between two similar figures' sides and lengths is a : b. The ratio between areas is $a^2 : b^2$.So if a : b is 12 : 18 which when simplifies is 2 : 3, what is $a^2 : b^2$?

anonymous · Answer

THANKS GUYS

anonymous · Answer

np :)