Question

a factor of 2x2+ 8x – 90

Answer 1

Firstly factor out 2 :

\[\large 2(x^2 + 4x - 45)\]

Answer 2

Now try to make factors:

\[ 2(x^2 + 4x - 45) \implies 2(x^2 + 9x - 5x - 45) \implies 2(x+9)(x-5)\]

Answer 3

first of all break out the middle term such that the product becomes 180x^2 & by adding them we gt 8x

Answer 4

\[\large{2x^2+8x-90}\]
\[\large{2x^2+18x-10x-90}\]
\[\large{2x(x+9)-10(x+9)}\]
\[\large{(2x-10)(x+9)}\]
\[\large{2(x-5)(x+9)}\]

Answer 5

Dudes ,but it is nt complete factoring so it should use quadratic formula

Answer 6

@sammyrayepatton did you get??

Answer 7

This method is known as : middle term splitting method :
It is @jiteshmeghwal9 we use quadratic formula to find roots .. as i think

Answer 8

We are not said to solve for x @jiteshmeghwal9

Answer 9

Note : we can not apply quadratic formula here since RHS \(\ne\) 0

Answer 10

RHS is not given to us ...

Answer 11

no after solving for x we wlll find the answer as\[(x- \alpha)(x- \beta)\]

Answer 12

There is not any RHS..

Or most often solve for x is the question..

Answer 13

but how to solve for x if RHS is not given

(only 1 arguemnt i pointed out .. there are many!!! )

Answer 14

k ! so now its solved:)