Question

MORE PROBABILITY :\
In a family with family with 4 children, excluding multiple births, what is the probability of having 2 girls and 2 boys, in that order? Assume that a boy is as likely as a girl at each birth.

Answer 1

That is more like using Pascal's triangle.

Answer 2

Refer to line 4:
1 4 6 4 1

Answer 3

1 ---> (4 girls)
4 ---> (3 girls, 1 boy)
6 ---> (2 girls, 2 boys)
4 ---> (3 boys, a girl)
1 ---> (4 boys)

Answer 4

Now, the probability of having 2 girls and 2 boys is \(\Large {6 \over \text{Sum of 1 + 4 + 6 + 4 + 1}}\)

Answer 5

ah hah !!

Answer 6

how do i know to look to line 4? Is it because they have 4 kids???

Answer 7

Yes, exactly :)

Answer 8

will this triangle always be set up the same??

Answer 9

sorry i know it is a dumb question lol

Answer 10

Yeah, have you ever heard of Pascal's Triangle? It remains the same :P

Answer 11

im taking all online so i am having a lil trouble lol, i am getting 21 but this is not one of my options :/

Answer 12

21? I told you that it's \[ 6 \over 1 + 4 + 6 + 4 + 1\]

Answer 13

1/8,1/4,1/2, or 1/16?

Answer 14

Huh?

Answer 15

omg sorry lol

Answer 16

i tend to overcomplicate things for some odd reason lol 1/16 , right in my face

Answer 17

Huh? Not 1/16.

Answer 18

What is \(1 + 4 + 6 + 4 + 1\)?

Answer 19

16

Answer 20

All right.
So what is \(\Large{6 \over 16}\)?

Answer 21

3/8

Answer 22

not in my solution options though

Answer 23

What? Oops.

Answer 24

yea i am stumped

Answer 25

Me too, in a way.

Answer 26

hmmmmm