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Mathematics 28 Online
OpenStudy (anonymous):

A drug company is running trials on a new test for anabolic steroids. The company uses the test on 400 athletes know to be suing steroids and 200 athletes known not to be using steroids. Of those using steroids, the new test is positive for 390 and negative for 10. Of those not using steroids, the test is positive for 10 and negative for 190. What is the estimated probability of a false negative result (the probability that an athlete using steriodes will test negative)?

OpenStudy (wach):

So, we're finding the probability of essentially a wrong result. Out of each group, how many people were misdiagnosed out of the total number tested in that group?

OpenStudy (anonymous):

those using steroids only yielded 10 wrong results

OpenStudy (anonymous):

and also 10 tested positive when they were not using

OpenStudy (anonymous):

???

OpenStudy (wach):

Yes, and for the other group, 10 were also misdiagnosed. So we can say that there is a 20/800 chance of the results being wrong. But we only want to find the probability of a false negative. How can we make the probability of 20:800 more concise, only applying to negative results?

OpenStudy (anonymous):

by dividing the options for negative results?

OpenStudy (wach):

Yes: So if 20/800 represents the wrong result in both groups, we can isolate only the people with negative response (10 people). What is the probability?

OpenStudy (anonymous):

.00025

OpenStudy (anonymous):

?

OpenStudy (wach):

You want to find: (number of people who got false negative result) / (total number of people tested)

OpenStudy (anonymous):

.025 ok so 10/400

OpenStudy (wach):

It would be out of 800, because that is the total amount of people in the entire experiment.

OpenStudy (anonymous):

only 400 in the total exeriment tho

OpenStudy (anonymous):

?

OpenStudy (anonymous):

20/600?

OpenStudy (anonymous):

.975,.95,.05,.025 are my options

OpenStudy (anonymous):

10/600 gives me .016667

OpenStudy (anonymous):

??

OpenStudy (wach):

What is the estimated probability of a false negative result (the probability that an athlete using steriodes will test negative)? Oh, so the probability is the misdiagnosed negative players / total athletes using steroids tested Thus, 0.025. I apologize for making this so confusing for you; the question confused me also.

OpenStudy (anonymous):

lol i know thats why i hatee probability ugh but everyone on here is so helpful !! whoever created this site is a genius.Thank you so much for clarifying for me your awesome!!

OpenStudy (wach):

You're welcome, and sorry for the confusion! >_<

OpenStudy (anonymous):

no problem thanks again i am going to become your fan if thats ok ?

OpenStudy (anonymous):

thanks again

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