Question

what is the simplified form of (2/x^2+x) - (1/x) ??
a.(x-1)/(x(x+1)
b.(1-x)/(x(x+1)
c.(3-x)/(x(x-1)
d.(x+2)/(x(x-1)

Thank you in advance !

Answer 1

a/b - c/d = (ad - bc)/bd
Here
a = 2, b = x^2+x, c = 1, d = x
so the common denominator b times d is (x(x+1)).

What is ad - bc?

Answer 2

sorry
denominator = x(x^2 + x)

Answer 3

I'm sorry but I don't know what ad-bc would be.

Answer 4

If we define
a = 2, b = x^2+x, c = 1, d = x
then your first equation is the same as
a/b - c/d
OK?

Answer 5

yes I'm following

Answer 6

So then ad = 2x and bc = .. and ad - bc = ..

Answer 7

x^2+x*1= x^2+x right since its times 1?

Answer 8

So now do the subtraction

Answer 9

Well, it's 2x - (x^2 + x) = 2x - x^2 - x = x - x^2 = x(1-x). That's your numerator

Answer 10

so would the final answer be (1-x)/(x(x+1)

Answer 11

?

Answer 12

Yes

Answer 13

We had to do some factoring at the end.

Answer 14

Thank you very much!