Question

plz help. I need someone to check my work.. is this right 5x^3/4y^4?

Answer 1

I'm guessing 5x^3/4y^4 is your answer?

Answer 2

If so, what's the question?

Answer 3

srry I have to pu load the pic.

Answer 4

ok

Answer 5

one second

Answer 6

okay. :)

Answer 7

unfortunately what you got is incorrect

Answer 8

is it this? I'm lost..5x^4/4y^3??

Answer 9

no it is not

Answer 10

can you show me how to do it?

Answer 11

\[\Large \frac{15x^5}{24y^8} \div \frac{8y^4}{4x^2}\]

\[\Large \frac{15x^5}{24y^8} \times \frac{4x^2}{8y^4}\]

Did you get this far?

Answer 12

okay gottcha.

Answer 13

then what's next?

Answer 14

you cross multipy. but 24 can go into 8 ...3 times. but then I get lost..

Answer 15

Well you multiply straight across, then you reduce as much as possible

\[\Large \frac{15x^5}{24y^8} \div \frac{8y^4}{4x^2}\]

\[\Large \frac{15x^5}{24y^8} \times \frac{4x^2}{8y^4}\]

\[\Large \frac{15x^5 \times 4x^2}{24y^8 \times 8y^4}\]

\[\Large \frac{60x^7}{192y^{12}}\]

\[\Large \frac{12*5x^7}{12*16y^{12}}\]

\[\Large \frac{\cancel{12}*5x^7}{\cancel{12}*16y^{12}}\]

\[\Large \frac{5x^7}{16y^{12}}\]

Answer 16

So the final answer is \[\Large \frac{5x^7}{16y^{12}}\]

Answer 17

I get how your breaking it down , But that's not one of my choices?

Answer 18

what are your choices?

Answer 19

1min

Answer 20

ok

Answer 21

is the problem really

\[\Large \frac{15x^5}{24y^8} \times\frac{8y^4}{4x^2}\]

Answer 22

and NOT with a division sign in the middle?

Answer 23

it with the divison sign

Answer 24

it's*

Answer 25

weird

Answer 26

i see the answer if it had a multiplication symbol and not a division symbol

Answer 27

you have it back words the last part. it shud be 4x^2/8y^4

Answer 28

So the actual problem is

\[\Large \frac{15x^5}{24y^8} \div\frac{4x^2}{8y^4}\]

???

Answer 29

yes.

Answer 30

ok that makes a ton more sense

Answer 31

\[\Large \frac{15x^5}{24y^8} \div \frac{4x^2}{8y^4}\]

\[\Large \frac{15x^5}{24y^8} \times \frac{8y^4}{4x^2}\]

\[\Large \frac{15x^5 \times 8y^4}{24y^8 \times 4x^2}\]

\[\Large \frac{120x^5y^4}{96x^2y^8}\]

\[\Large \frac{24*5x^5y^4}{24*4x^2y^8}\]

\[\Large \frac{\cancel{24}*5x^5y^4}{\cancel{24}*4x^2y^8}\]

\[\Large \frac{5x^5y^4}{4x^2y^8}\]

\[\Large \frac{5x^{5-2}y^{4-8}}{4}\]

\[\Large \frac{5x^3y^{-4}}{4}\]

\[\Large \frac{5x^3}{4y^{4}}\]

Answer 32

thank you very much, your a big help

Answer 33

i'm glad, yw