If you have 310.0 mL of water at 25.00 °C and add 140.0 mL of water at 95.00 °C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

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anonymous · Answer

@zbay

anonymous · Answer

Using the first law of thermodynamics (I'm not sure about if it's the first)
ΔU = Q + ΔW=0( you need more hypothesis to do this)
 ΔU_1+ΔU _2=0 
m_1 :  mass of 310.0 mL of water
m_2 : mass  of 310.0 mL
$$m_1c(T_f-T_0)+m_2c(T_f-T_1)=0$$
$$T_f=\frac{m_1T_1+m_2T_2}{m_1+m_2}$$
is that chemistry or  thermodynamic !

anonymous · Answer

uhh..chemistry

anonymous · Answer

uhhh.. i don't understand the formula