Determine the type of boundary line and shading for the graph of the inequality 2x + y > 4.
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jimthompson5910 (jim_thompson5910):
Any ideas?
OpenStudy (anonymous):
no, confused
OpenStudy (anonymous):
i mean, i dont understand it.
jimthompson5910 (jim_thompson5910):
Solve for y to get
2x + y > 4
y > 4-2x
y > -2x+4
jimthompson5910 (jim_thompson5910):
So we shade above the line since we have a greater than symbol
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jimthompson5910 (jim_thompson5910):
The line is also a dotted line because we're NOT including the boundary
jimthompson5910 (jim_thompson5910):
If we were, we'd be using a \(\Large \ge\) sign
OpenStudy (anonymous):
yeahh?
jimthompson5910 (jim_thompson5910):
does that make sense?
OpenStudy (anonymous):
sort of
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jimthompson5910 (jim_thompson5910):
So that's the type of boundary line on something like y < 2x+3
Dotted?
or
Solid?
OpenStudy (anonymous):
dotted
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
because the < symbol tells us we're not including the boundary
jimthompson5910 (jim_thompson5910):
and the dotted line means ignore the boundary
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OpenStudy (anonymous):
oh ok
OpenStudy (radar):
Have you plotted your line yet?
OpenStudy (radar):
If you haven't I would like to suggest two points to use.
OpenStudy (anonymous):
Okay
OpenStudy (radar):
One point would be P1(2,0) and the other one would be P2(0,4) These are intercepts and using a straight edge you can draw the line, and as jim_thompson has explained draw a dotted line rather than a solid one.