Question

let f(x)=(6x-7)^5 and find f"(x)

Answer 1

have you differentiate it yet?

Answer 2

\[f(x) = (6x-7)^5\]
\[f'(x) = 5(6x-7)^4*6\]

Answer 3

\[ => f'(x)= 30*(6x-7)^4\]

Answer 4

yeh u did the first step

Answer 5

now its your turn to differentiate it again :)

Answer 6

use the product rule

Answer 7

could we say diff like this 120(6x-7)^3

Answer 8

is there something left for us knw

Answer 9

\[f'(x) = 30*(6x-7)^4\]
\[ f"(x) = 120(6x-7)^3*6\]

Answer 10

i suppose you can do it like that

Answer 11

that was suppose to be \(f''(x)=....\)

Answer 12

i argued with a friends , they said it will stop up to 720(6x-7)^2

Answer 13

\[f"(x) = 720 (6x-7)^3\]

Answer 14

am i right up to this point Omni

Answer 15

http://www.wolframalpha.com/input/?i=second+derivative%286x-7%29^5

Answer 16

wolfram agrees with me; its not 720(6x-7)^2

Answer 17

do u mean it will stop here 720(6x-7)^2

Answer 18

that is not right

Answer 19

the answer i wrote is right and wolfram agrees with me; there is a low chance that me and wolfram are wrong

Answer 20

no no i just believe in u and am thankfull to u and ur is right