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OpenStudy (anonymous):
Solve for m.
m
9
=
25
m
A)
± 216
B)
± 225
C)
± 14.6
D)
± 15
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OpenStudy (anonymous):
This is a proportion. It should look like m/9 = 25/m
Parth (parthkohli):
1) Multiply both sides by 9.
2) Multiply both sides by m.
3) Solve the quadratic equation that you get.
OpenStudy (lgbasallote):
cross multiply
\[\frac m9 = \frac{25}{m}\]
\[m^2 = 25\times 9\]
\[m^2 = 225\]
\[m = \pm \sqrt{225}\]
\[m = \pm 15
OpenStudy (theviper):
Cross multiply :-
\[\Large{\frac{m}{9}=\frac{25}{m}}\]\[\Large{m \times m=25 \times 9}\]\[\LARGE{{m^2=225}}\]
OpenStudy (anonymous):
what do you mean by both sides?
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Parth (parthkohli):
Never mind, that is not a quadratic equation.
OpenStudy (lgbasallote):
\[m = \pm 15\]
is what i meant in my last line
OpenStudy (theviper):
\[\Huge{m=\pm 15}\]
OpenStudy (anonymous):
OHHHHHH OKAY! I get it lol I miss-read it
OpenStudy (anonymous):
cross multiplication method is easy for you.
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OpenStudy (theviper):
Understood??
OpenStudy (anonymous):
Thanks @muhammad9t5 @TheViper @Igbasallote and @ParthKohli !!!!!!
Parth (parthkohli):
You're welcome! :)
OpenStudy (theviper):
Most Welcome :)
OpenStudy (anonymous):
I would not actually do the multiplication of 9 times 25… FWIW
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