Calculus. s=(t^3)/3 -6t^2 +50t with what value of t does the object have a minimum velocity.
ive worked the velocity equation out by differentiating the equation, and have got t^2 -12t +50
so then t^2 -12t +50 =0
i cant factorise this to find the points by which the gradient = 0
then use the quadratic formula
in case you forgot\[ax^2+bx+c=0\implies x={-b\pm\sqrt{b^2-4ac}\over2a}\]
ah ok, havent used that in ages, cheers mate
i need to get 6
and using this formula i just get a mathematics error
oh I didn't read your Q carefully enough, my bad...
no worries mate
you are given a function for position, and you want to minimize velocity velocity is the first derivative of position to find max/mins for the velocity function you have to take the derivative again, and set \(that\) equal to zero
why do you take the second derivative? the second derivative is the derivative of a quadratic
thus being linear
to find the max/mins of any function take the derivative and set it to zero
could you please explain this to me, the second derivative is meant to give a point of inflection or tell you the nature of a turning point, so says my maths teacher
but when i set the equation to 0 i get an equation that is unfactorable
you are given position, derivative of position is velocity to find the max/min of the velocity function though you must set the derivative of *that function* equal to zero yes setting the second derivative of the position function equal to zero will also tell you a point of inflection, but for the *position* function, not the velocity one you already have the velocity function, so take the derivative of that and set it to zero
ah yes i see now, so taking the derivative of the velocity function will give you the maximum/minimum of it. But since the velocity function is a parabola it will only give you a max or min
Cheers for that mate ;)
solving s(t)=0 tells you when position is zer solving s'(t)=0 tells you the max/mins of the position and when the velocity is zero we don't want that, we want to know the max/mins of the velocity function so solve s''(t)=0 you're welcome (from across the pond I assume)!
haha yes, guess you can tell where then haha.
judging by the term im assuming your british?
no, but my stepfather is so I'm quite familiar with British English I'm a US citizen living in Mexico
Ah, interesting. Well Aussie here mate, haha, cheers for the help. Not familiar with the time zones, but i believe its day time over there, so have a good day mate.
ah, then you're more than the "pond" away :P see ya around!
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