Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

simplify the radical in my comment since i don't know how to on here :l

OpenStudy (anonymous):

\[\sqrt{75x}\] the x is squared

OpenStudy (anonymous):

\[\sqrt{ab} = \sqrt{a} \sqrt{b}\]

OpenStudy (anonymous):

ok so it is \[\sqrt{75}\] x \[\sqrt{x ^{2}}\]

OpenStudy (anonymous):

What I meant to suggest is that 75 can be factored so that one of the factors is a perfect square. Namely 25.

OpenStudy (theviper):

\[\Huge{\sqrt{75}\times \sqrt{x^2}}\]?????? Is ur question this??

OpenStudy (theviper):

or\[\Huge{\sqrt{75x^2}}\]

OpenStudy (waleed_imtiaz):

I can't understand the question properly....

OpenStudy (anonymous):

I see. But still, the \[\sqrt{75}\] can be simplified too.

OpenStudy (anonymous):

it says simplify. assume all variable represent positive values. then it gives me this expression. \[\sqrt{75x ^{2}}\]

OpenStudy (anonymous):

So this can be factored into \[\sqrt{25}\] \[\sqrt{3}\] \[\sqrt{x^2}\]

OpenStudy (anonymous):

Should be all on one line.

OpenStudy (theviper):

\[\Large{\sqrt{75x^2}=\sqrt{5\times5\times3\times x \times x}=5x \sqrt{3}}\]

OpenStudy (anonymous):

so i should do a "factor tree" for the 75 and since the x is squared it is x times x

OpenStudy (anonymous):

so did you get this all figured out?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!