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What is the sum of an 8-term geometric sequence if the first term is 10 and the last term is 781,250?
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the formula is: \[first\frac{1-r^n}{1-r}\]
first you need to find value of common ratio r r^7 = 782, 250 / 10 = 78250
\[Sum = \frac{a(r^n - 1)}{(r-1)}\]
\[r^7 = 78125\] Find r..
r = 5
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given that\[a_n=a_1*r^{(n-1)}\] \[\left(\frac{a_n}{a_1}\right)^{\frac{1}{n-1}}=r\] that was tough to type in lol
i Got 976,560
is that right?
\[Sum = \frac{10((5)^8 - 1)}{(5-1)}\]
Well Done..
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You are right..
thank you! all Of You!
Welcome dear.
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