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Mathematics 19 Online
OpenStudy (anonymous):

What is the inverse of the sine function?

OpenStudy (zzr0ck3r):

so with sine you put in an angle and get out a number, with sine inverse you put in that number and get out that angle(if the domain is limited) it gets sort of tricky without the limited domain because every inverse will have infinite answers. like sine inverse of 1 is pi/2, 5pi/2, 9pi/2......forever.

OpenStudy (across):

Let \(0\leqslant\theta<2\pi\). Then\[\sin^{-1}(\sin(\theta))=\theta.\]

OpenStudy (zzr0ck3r):

ha, much more elegent.

OpenStudy (anonymous):

i don't think that's right.... to get the inverse of the sine function, the domain of sine function is restricted to [-pi/2, pi/2] so this will be the RANGE of the inverse sine (or arcsin) function. The domain of the arcsine function is [-1, 1]...

OpenStudy (zzr0ck3r):

o yeah I didnt reven read the angles it is for sure -pi/2, pi/2

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