Rewrite the expression in terms of the given function or functions. (sec x + csc x) (sin x + cos x) - 2 - cot x; tan x
A. 0
B. 2tan x
C. tan x
D. 2 + tan x
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OpenStudy (anonymous):
I got C is that right?
OpenStudy (helder_edwin):
is the expression like this
\[ \large (\sec x+\csc x)(\sin x+\cos x)-2-\cot x/\tan x \]
OpenStudy (campbell_st):
well rewrite the brackets and simply that 1st
\[(\frac{1}{\cos(x)} + \frac{1}{\sin(x)})\times (\sin(x) + \cos(x)) \]
\[\frac{\sin(x)}{\cos(x)} + 1 + 1 + \frac{\cos(x)}{\sin(x)}\]
simplifies to \[\tan(x) + \cot(x) + 2\]
so the equation becomes
\[\tan(x) + \cot(x) + 2 - 2 -\cot(x) = \tan(x)\]
hope it helps
OpenStudy (anonymous):
thnx!
OpenStudy (anonymous):
wait i dont understand the second step..
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OpenStudy (anonymous):
@campbell_st
OpenStudy (campbell_st):
the expansion...?
OpenStudy (anonymous):
sin(x)/cos(x)+1+1+cos(x)/sin(x)
OpenStudy (anonymous):
@campbell_st
OpenStudy (anonymous):
can someone explain the step to me?
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OpenStudy (anonymous):
just expand the previous line... it's like FOILing....
OpenStudy (anonymous):
ohh i get it! thnx @dpaInc
OpenStudy (campbell_st):
its just the multiplication
1/sin(x) * sin(x) = 1
1/cos(x) * cos(x) = 1
1/cos(x) * sin(x) = sin(x)/cos(x) = tan(x)
1/sin(x) * cos(x) = cos(x)/sin(x) = cot(x)