Mathematics
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OpenStudy (anonymous):
(a^5b^3) (a^4b^5)
Do I multiply for add the exponents? E.g. would I have a^9 or a^20? Thank you!
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jimthompson5910 (jim_thompson5910):
You add the exponents in this case
OpenStudy (anonymous):
Oh my goodness... THANK YOU!!!!! Last time I had to ask this question, I was forced to wait 10 minutes for a wrong answer.
jimthompson5910 (jim_thompson5910):
you're welcome
OpenStudy (anonymous):
So it is a^9andb^8 correct?
jimthompson5910 (jim_thompson5910):
bingo
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OpenStudy (anonymous):
THANK YOU! Can you answer one more quick question, please?
jimthompson5910 (jim_thompson5910):
so \[\Large a^9b^8\]
OpenStudy (anonymous):
(-2hi^3)(2h^2ij^3)
jimthompson5910 (jim_thompson5910):
multiply -2 and 2 to get?
OpenStudy (anonymous):
Would it be -4h^3i^4j^7?
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jimthompson5910 (jim_thompson5910):
The term for j is j^3 since the first expression doesn't have any j terms
jimthompson5910 (jim_thompson5910):
or because
(-2hi^3)(2h^2ij^3)
really is
(-2hi^3j^0)(2h^2ij^3)
jimthompson5910 (jim_thompson5910):
So i'm not sure how you're getting 4+3 = 7
OpenStudy (anonymous):
-4h^2i^3j^12?
jimthompson5910 (jim_thompson5910):
no
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jimthompson5910 (jim_thompson5910):
What are the exponents for j in
(-2hi^3j^0)(2h^2ij^3)
???
OpenStudy (anonymous):
Do I not multiply -2 and 2?
jimthompson5910 (jim_thompson5910):
yes those are the coefficients
OpenStudy (anonymous):
0 and 3
jimthompson5910 (jim_thompson5910):
add them
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jimthompson5910 (jim_thompson5910):
to get the final exponent for j
OpenStudy (anonymous):
3
jimthompson5910 (jim_thompson5910):
So the answer is \[\Large -4h^3i^4j^3\]
OpenStudy (anonymous):
Thank you!!
jimthompson5910 (jim_thompson5910):
yw
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OpenStudy (anonymous):
Okay now, another one! :D
([3^2]^3g^5h^8)^2
jimthompson5910 (jim_thompson5910):
What is [3^2]^3
OpenStudy (anonymous):
Do you mind if I do the problem by myself, and I'll give you my answer and see if I'm right?
jimthompson5910 (jim_thompson5910):
alright
OpenStudy (anonymous):
Stay with me, please! :)
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jimthompson5910 (jim_thompson5910):
ok
OpenStudy (anonymous):
729g^10h^16
OpenStudy (anonymous):
Yes?
jimthompson5910 (jim_thompson5910):
no it's not correct
OpenStudy (anonymous):
Huh..
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jimthompson5910 (jim_thompson5910):
3^2 is 9
So [3^2]^3 = 9^3 = 729
This means
([3^2]^3g^5h^8)^2
becomes
(729g^5h^8)^2
jimthompson5910 (jim_thompson5910):
did you get that as one of your steps?
OpenStudy (anonymous):
Uhm
OpenStudy (anonymous):
yes
jimthompson5910 (jim_thompson5910):
Then you square everything inside
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OpenStudy (anonymous):
Oh!
jimthompson5910 (jim_thompson5910):
tell me what you get
OpenStudy (anonymous):
531,411g^10h^13
OpenStudy (anonymous):
16
jimthompson5910 (jim_thompson5910):
yes, but I would get rid of the comma....computer answer systems don't like commas
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jimthompson5910 (jim_thompson5910):
oh yes, 16 not 13
jimthompson5910 (jim_thompson5910):
use only commas to separate out answers (like ordered pairs), don't enter commas for large numbers
OpenStudy (anonymous):
kk
jimthompson5910 (jim_thompson5910):
so the answer is
531411g^10h^16
which looks like
\[\Large 531411g^{10}h^{16}\]
OpenStudy (anonymous):
uhm
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jimthompson5910 (jim_thompson5910):
what's wrong?
OpenStudy (anonymous):
x(x^4)(x^6)
jimthompson5910 (jim_thompson5910):
x = x^1
OpenStudy (anonymous):
x^11?
jimthompson5910 (jim_thompson5910):
So
x(x^4)(x^6)
is the same as
x^1(x^4)(x^6)
or
x^1 times x^4 times x^6
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jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
x(x^4)(x^6) = x^11
OpenStudy (anonymous):
Okay, one more question! :)
jimthompson5910 (jim_thompson5910):
ok
OpenStudy (anonymous):
|dw:1343517212128:dw|