What is the length of the diagonal AC in the rectangle below? A. 10.30 B. 5 C. 9 D. 9.06
Firstly find the coordinates of the Point A and Point C..
\[\large{AC^2=AD^2+CD^2}\]
(-5,3) and (4,-2)
For A it is (-5, 3) and For C it is (4,-2) Now apply the distance formula..
Find the value of AD = 3+2=5 and CD = 4 + 5 =9
\[\large Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]
\[\large{5^2+9^2=25+81=106=AC^2}\] \[\large{AC=\sqrt{106}=10.29..=10.30(approx.)}\]
*much easier way to do* .. got it @dasDaName ?
so its A.
yes..
yea, i got it. ty for both
no problem best of luck
thanks again
The method pointed out by @waterineyes is universal for these type of problems though here @mathslover has an easier soln good work to both
\[\large Distance = \sqrt{(9)^2 + (-5)^2} = \sqrt{106} \approx 10.30\] You can apply both you will get the same..
ty
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