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OpenStudy (anonymous):
What is the length of the diagonal AC in the rectangle below?
A. 10.30
B. 5
C. 9
D. 9.06
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OpenStudy (anonymous):
OpenStudy (anonymous):
Firstly find the coordinates of the Point A and Point C..
mathslover (mathslover):
\[\large{AC^2=AD^2+CD^2}\]
OpenStudy (anonymous):
(-5,3) and (4,-2)
OpenStudy (anonymous):
For A it is (-5, 3) and For C it is (4,-2)
Now apply the distance formula..
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mathslover (mathslover):
Find the value of AD = 3+2=5
and CD = 4 + 5 =9
OpenStudy (anonymous):
\[\large Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]
mathslover (mathslover):
\[\large{5^2+9^2=25+81=106=AC^2}\]
\[\large{AC=\sqrt{106}=10.29..=10.30(approx.)}\]
mathslover (mathslover):
*much easier way to do* .. got it @dasDaName ?
OpenStudy (anonymous):
so its A.
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mathslover (mathslover):
yes..
OpenStudy (anonymous):
yea, i got it. ty for both
mathslover (mathslover):
no problem best of luck
OpenStudy (anonymous):
thanks again
OpenStudy (vishweshshrimali5):
The method pointed out by @waterineyes is universal for these type of problems
though here @mathslover has an easier soln
good work to both
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OpenStudy (anonymous):
\[\large Distance = \sqrt{(9)^2 + (-5)^2} = \sqrt{106} \approx 10.30\]
You can apply both you will get the same..
OpenStudy (anonymous):
ty
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