Mathematics
19 Online
OpenStudy (anonymous):
If f(x)=4x+7 and g(x)= sqrt(x-3), what is (fog)(4)
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OpenStudy (anonymous):
keep getting these square root ones wrong. medal to correct answer
OpenStudy (lgbasallote):
lol bribing?
OpenStudy (anonymous):
well, just want people to double check there answer
OpenStudy (lgbasallote):
well what's your answer
OpenStudy (anonymous):
lemme do it
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OpenStudy (lgbasallote):
tag me when you have an answer
OpenStudy (anonymous):
\[\sqrt{23-3}\]
4.4721
but thats not right.
OpenStudy (anonymous):
@lgbasallote
OpenStudy (lgbasallote):
solve for g(4) first
OpenStudy (lgbasallote):
\[(f o g)(4) \implies f(g(4))\]
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OpenStudy (anonymous):
ahhh, so 11
OpenStudy (lgbasallote):
yup
OpenStudy (anonymous):
here is one that introduces h @lgbasallote Let f(x)=(4x^3+20)^2 and g(x)=4x^3+20. Given that f(x)=(hog)x, find h(x)
OpenStudy (anonymous):
where do i start with that
OpenStudy (lgbasallote):
find (h o g) x first
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OpenStudy (vishweshshrimali5):
see the examples. .
you may continue @lgbasallote
OpenStudy (anonymous):
this may help, in helping me
OpenStudy (anonymous):
wait, how do i find (hog)?
OpenStudy (lgbasallote):
find g(x) first
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OpenStudy (lgbasallote):
what is g(x)
OpenStudy (anonymous):
what do i use for x?
OpenStudy (lgbasallote):
x
OpenStudy (anonymous):
isnt it just 4x^3+20 then?
OpenStudy (lgbasallote):
yup
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OpenStudy (lgbasallote):
so therefore
h(4x^3 + 20) = f(x) do you agree with this?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
where do i use that?
OpenStudy (lgbasallote):
hmm this was easier in my head...
OpenStudy (anonymous):
lol
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OpenStudy (lgbasallote):
how will you turn h(4x^3 + 20) into h(x) what do you think?
OpenStudy (anonymous):
geeze, I have no clue.
OpenStudy (lgbasallote):
me neither :/
OpenStudy (lgbasallote):
try posting it as a new question maybe someone has an idea