Simplify the expression. If the simplified expression is written in standard form, what is the leading coefficient?
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Firstly solve for : \[\large x \sqrt{64x^3} \implies x \sqrt{8 \times 8 \times x \times x \times x}\]
So you can take one 8 and one x out: \[\large \implies x \times 8 \times x \sqrt{x}\] \[\large \implies 8x^2 \sqrt{x}\]
So the leading coefficient is 8?
This is for first term only..
Okay
No need to solve for second term as it is simplified.. Now for third you can write: \[\large 8 \sqrt{2x} \implies 8 \sqrt{2} \times \sqrt{x} \implies 8 \sqrt{2} \cdot \sqrt{x}\]
Now you can take root(x) as common from all: \[\implies \color{green}{\large \sqrt{x}[8x^2 + 2x + 8\sqrt{2}]}\]
In my view It cannot be factorized further..
Okay. But the leading coefficient is still 8 right?
Do you have answer choices with you??
no its a fill in the blank
I am guessing why are you concentrating on 8 ?
because its the first coefficient
yes its 8
okay thank you!
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