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Mathematics 17 Online
OpenStudy (anonymous):

For a particular sample of 58 scores on a psychology exam, the following results were obtained. First quartile = 52 Third quartile = 84 Standard deviation = 10 Range = 66 Mean = 79 Median = 78 Mode = 81 Midrange = 65 Answer each of the following: I. What score was earned by more students than any other score? Why? II. What was the highest score earned on the exam? III. What was the lowest score earned on the exam? IV. According to Chebyshev's Theorem, how many students scored between 59 and 99? V. Assume that the distribution is normal. Based on the Emp

OpenStudy (anonymous):

The first one is easy, right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Now, http://en.wikipedia.org/wiki/Mid-range

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

So the top score is half the range above the midrange and the bottom score is half the range below the midrange. Yes?

OpenStudy (anonymous):

i 'm not sure

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Chebyshev%27s_inequality the precise statement being that no more than 1/k^2 of the distribution’s values can be more than k standard deviations away from the mean.

OpenStudy (anonymous):

We'll go back to Chebyshev. The midrange is by definition the average of the top and bottom scores.

OpenStudy (anonymous):

OK with that?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Back now

OpenStudy (anonymous):

So we have top and bottom scores and the midrange is half way in between, so half the range is above it and half below.

OpenStudy (anonymous):

Now back to Chebyshev. You'll notice in part IV they ask about the scores between 59 and 99, that is, between 2 SD below the mean and 2 SD above it. OK?

OpenStudy (anonymous):

So Chebyshev says no more than 1/k^2 of the distribution’s values can be more than k standard deviations away from the mean. We're looking at k = 2 So he'd say that no more than 1/4 of the scores are outside the range 59-99 and therefore 3/4 must be inside that range.

OpenStudy (anonymous):

OK with that?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

What's the last question? I can't quite make it out.

OpenStudy (anonymous):

Assume that the distribution is normal. Based on the Empirical Rule, how many students scored between 69 and 89?

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