If the force of gravity between a book of mass 0.50 kg and a calculator of 0.100 kg is 1.5 × 10-10 N, how far apart are they? Note: The distance found is between the centres of mass.
Force = G m1 m2 / r^2
Do I have to convert the mass into g?
nah. take them as it is (in kg)
\[1.5 x 10^{-11} N = (6.67 x 10^{-11} N*m ^{2}/kg ^{2}) (0.50 kg) (0.100kg) / r ^{2}\]
\[r ^{2}= \sqrt(6.67 x 10^{-11} N*m ^{2}/ kg ^{2} (0.50kg) (0.100kg) / 1.5 x 10^{-10} N\]
= 1.49 x 10^-11
\[=1.49 x 10^{-11} m\]
Is that correct?
@telltoamit
@maheshmeghwal9
@CarlosGP
Your formula is ok:\[ r=\sqrt{Gm_1m_2/F}=\sqrt{6,67\times10^{-11}\times 0.5 \times0.1/1.5\times10^{-10}}=\sqrt {???}=???m\] But you made an error in the calculation, they are much, much closer
Give your result and I'll check it
I have no idea.
@CarlosGP: I think you mean much, much *farther* apart. @Daeno: The answer you gave was\[1.49 x 10^{-11} m\]So something went wrong in your calculation of the exponents. It should have been:\[0.149m\]
I do not know what made me think of 14.9 cm shorter than 14.9 pico-meters. Things of the age, surely. Thanks for the correction
Happens to me all the time :)
Equations+Exponents+English as Second Language=Fatal Errors :)
lol...I don't even have the second language excuse!
I don't know where I went wrong with the equation.
Can someone please clarify on what I should've done?
ya answer is 0.149 meters. as @Shane_B is correct 100%. u made calculation mistake @Daenio :/ just improve that:)
Can you break down the calculation because I don't know how to get 0.149m.
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