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Mathematics 16 Online
OpenStudy (swissgirl):

The relation T on R X R is given by (x,y)T(r,s) iff x+y=r+s is symmetric

OpenStudy (swissgirl):

Now if I had to prove that it is symmetric I wld have to prove it showing that if (x,y)T(r,s) then (r,s)T(x,y) right?

OpenStudy (swissgirl):

Like i have to correct proofs and the proof they give for this claim is: xSuppose (x,y) \( \in R X R \) then (x,y) T(y,x) because x+y =y+x. Therefore T is symmetric

OpenStudy (swissgirl):

Like this proof is incorrect but to correct it i wld have to prove it that if x+y=r+s then r+s =x+y?

OpenStudy (kinggeorge):

You're correct in assuming that to show that T is symmetric you have to show that if (x,y)T(r,s) then (r,s)T(x,y). However, you don't have to show that x+y=r+s is symmetric. That part is given to you.

OpenStudy (swissgirl):

alrighty thanks :DDDDDDDDDDDDDDDDDDDDDDDD

OpenStudy (swissgirl):

It kinda feels weird that like any question i have I come on here and you answer my questions for free. idkkkkkkkkkkkkkk

OpenStudy (kinggeorge):

But you're actually making an effort to try the problems yourself. And I enjoy this subject area. =D

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