Question

i already did the problem but i need to know whether its right or not

Answer 1

Part 1:
Graphing: Is when you want a visual display of the equations or when you want to estimate a solution.

Substitution: Is when one equation is already solved for one of the variables or when it is easy to solve for one of the variables.

Elimination: Is when the coefficients of one variable are the same or opposites or when it is not convenient to use graphing or substitution.

Part 2: I used (-y + 3x = 6) (y = -6x + 12)
So how I did this was I did (-6 + 12) + 3x -6. So -6 + 12 is 6. Then I did 6x + 3x -6 - 12. So 6x + 3x is 9x, and -6 -12 is -18. Then I did 9x divided by 9x and that canceled out. Then I did -18 divided by 9 is -2. So x is -2. Then I did -6(2) + 12 and -6 times 2 is -12. Then I did -12 + 12 which equals to 0. So y = 0. So the solution to this problem is (0,-2).

Answer 2

just tell my if i did it the like right way

Answer 3

y = -6x + 12

put this value in first one:


\[-(y) + 3x - 6 = 0\]

\[6x - 12 + 3x - 6 = 0 \implies 9x = 18 \implies \color{green}{x = 2}\]

Answer 4

Now find y:

\[y = -6x + 12 \implies y = -6(2) + 12 \implies -12 + 12 \implies \color{green}{y = 0}\]

Answer 5

So the solution will be \((2,0)\)..

Answer 6

thanks that was very helpful