Question

give exact and approximate solutions to three decimal places x^2+14x+49=25

Answer 1

u can use the cuadratic formula: given \(ax^2+bx+c=0\) then
\[ \large x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \]

Answer 2

do u know how to use this?

Answer 3

I'm learning. The answer I come up with is -2,-12

Answer 4

u got it right!

Answer 5

aahhh...thx

Answer 6

factor out both sides
\[x^2 + 14x + 49 = 25\]
\[(x+7)^2 = 25\]
ge the square root of both sides
\[x + 7 = \pm 5\]
subtract 7 from both isdes
\[x = \pm 5 - 7\]
therefore x = -2; x = -12

Answer 7

in this case what @lgbasallote did is quite more elegant.
the formula is the "easiest" way, but can be "crude".

Answer 8

i think fourth-dimensionally :DDD