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-10/1-2i simplified
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is it \[ \large \frac{-10}{1-2i} \]
you have to get rid of the imiganary i in denominator by multiplying by its complex conjugate
Multiply and divide with 1+2i
yes @helder_edwin
\[\Large \frac{-10}{1-2i}*\frac{1+2i}{1+2i}\]
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well as @timo86m said \[ \large \frac{-10}{1-2i}\cdot\frac{1+2i}{1+2i}= \] can u go on
and use that fact that i*i=-1
\[\Large \frac{-10-20i}{(1)^2-(2i)^2}\]
\[\Large \frac{10-20i}{1-4i^2}=\frac{10-20i}{1-(-1)(4)}\]
just add in denominator !!!
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@katiebugg did you get it?
|dw:1343618788526:dw|
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