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Mathematics 16 Online
OpenStudy (anonymous):

-10/1-2i simplified

OpenStudy (helder_edwin):

is it \[ \large \frac{-10}{1-2i} \]

OpenStudy (anonymous):

you have to get rid of the imiganary i in denominator by multiplying by its complex conjugate

OpenStudy (anonymous):

Multiply and divide with 1+2i

OpenStudy (anonymous):

yes @helder_edwin

OpenStudy (anonymous):

\[\Large \frac{-10}{1-2i}*\frac{1+2i}{1+2i}\]

OpenStudy (helder_edwin):

well as @timo86m said \[ \large \frac{-10}{1-2i}\cdot\frac{1+2i}{1+2i}= \] can u go on

OpenStudy (anonymous):

and use that fact that i*i=-1

OpenStudy (anonymous):

\[\Large \frac{-10-20i}{(1)^2-(2i)^2}\]

OpenStudy (anonymous):

\[\Large \frac{10-20i}{1-4i^2}=\frac{10-20i}{1-(-1)(4)}\]

OpenStudy (anonymous):

just add in denominator !!!

OpenStudy (anonymous):

@katiebugg did you get it?

OpenStudy (anonymous):

|dw:1343618788526:dw|

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