Question

ok simplify

Answer 1

\[a ^{2}\sqrt{8} /\sqrt{16a^{2}}\]

Answer 2

\[\sqrt{8} = \sqrt{4}*\sqrt{2}\]
\[\sqrt{16a^{2}} = \sqrt{16}*\sqrt{a^{2}}\]
that should help

Answer 3

not really lol sorry

Answer 4

what is sqrt(4) ?

Answer 5

what??

Answer 6

do you know what the the square root of 4 is?

Answer 7

ok how about 16?

Answer 8

2 and 4...

Answer 9

yep, now a^2

Answer 10

@dumbcow u lost me a long time ago

Answer 11

\[\sqrt{16} = \sqrt{4^{2}} = 4\]
so for any number
\[\sqrt{a^{2}} = a\]

Answer 12

lol ur not hepling my question tho...

Answer 13

well to simplify the problem , you need to simplify or get rid of the radicals, that is what im trying to help you do

Answer 14

dont u just multiply the top by the bottom???

Answer 15

you want someone to answer your problem?

find the square root of 14 of a^2 and sqrt(4)*sqrt(2)

Answer 16

\[\frac{\sqrt{8} a^{2}}{\sqrt{16a^{2}}} = \frac{\sqrt{4}\sqrt{2}a^{2}}{\sqrt{16}\sqrt{a^{2}}} = \frac{2\sqrt{2}a^{2}}{4a}\]

Answer 17

@dumbcow ok now i seee ima sorry about that

Answer 18

np :)
now just reduce to get final answer

Answer 19

lol thanks!!