Similar to how the distance formula can be modified to get 3 dimensions, can the same be done to the slope-formula?
the slope is the tangent of the angle between the line and the positive direction of the x-axis
i guess that, in 3d, you could measure the angle between the line and the xy-plane and call its tangent the slope.
Well, I'm asking this from the context that I have to find the area of a triangle using three dimensional coordinates...
but if u r given two lines perpendicular to each other would the product of the slopes still be -1?
Not quite sure...really...
but if u have the 3 points that define the triangle u can measure the lengths of the sides and use (i'm not sure of the name) heron's formula
Yeah. I know. It was just a spur of the moment question out of curiosity...
for 3-d, its better to think of slope as a directional vector with 3 components the slope in 2-d is just a vector with 2 components: <1,m>
I haven't done vectors, so for now, I'll just think that I shouldn't be using it yet. THanks! :)
oh nevermind then...then how are you supposed to determine slope in 3-d?
what level math are you in ?
Algebra II, borderline pre-calc. Like I said, it was a spur of the moment question out of curiosity, so if I shouldn't know how to do it yet, I'll just save it for later.
haha yeah it will come later, vectors usually at end of pre-calc so to answer your question, the formula for finding slope in 3-d is not quite as simple as the easy modification of distance formula
Alright. Thank you :)
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